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d^2+17d-18=0
a = 1; b = 17; c = -18;
Δ = b2-4ac
Δ = 172-4·1·(-18)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-19}{2*1}=\frac{-36}{2} =-18 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+19}{2*1}=\frac{2}{2} =1 $
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